3[x+-1(4x+-1)]=3(2x+-5)

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Solution for 3[x+-1(4x+-1)]=3(2x+-5) equation:


Simplifying
3[x + -1(4x + -1)] = 3(2x + -5)

Reorder the terms:
3[x + -1(-1 + 4x)] = 3(2x + -5)
3[x + (-1 * -1 + 4x * -1)] = 3(2x + -5)
3[x + (1 + -4x)] = 3(2x + -5)

Reorder the terms:
3[1 + x + -4x] = 3(2x + -5)

Combine like terms: x + -4x = -3x
3[1 + -3x] = 3(2x + -5)
[1 * 3 + -3x * 3] = 3(2x + -5)
[3 + -9x] = 3(2x + -5)

Reorder the terms:
3 + -9x = 3(-5 + 2x)
3 + -9x = (-5 * 3 + 2x * 3)
3 + -9x = (-15 + 6x)

Solving
3 + -9x = -15 + 6x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6x' to each side of the equation.
3 + -9x + -6x = -15 + 6x + -6x

Combine like terms: -9x + -6x = -15x
3 + -15x = -15 + 6x + -6x

Combine like terms: 6x + -6x = 0
3 + -15x = -15 + 0
3 + -15x = -15

Add '-3' to each side of the equation.
3 + -3 + -15x = -15 + -3

Combine like terms: 3 + -3 = 0
0 + -15x = -15 + -3
-15x = -15 + -3

Combine like terms: -15 + -3 = -18
-15x = -18

Divide each side by '-15'.
x = 1.2

Simplifying
x = 1.2

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